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Let $\omega\in\Lambda^kV^*$ and $\eta\in\Lambda^lV^*$

Show that \begin{equation} \omega\wedge\eta=\frac{(k+l)!}{k!l!}Alt(\omega\otimes\eta) \end{equation}

What i know:

$(\omega\wedge\eta)(v_1,...,v_k,v_{k+1},...,v_{k+l}) =\frac{1}{k!l!}\sum_{\sigma\in S_{k+l}} sgn(\sigma)\omega(v_{\sigma(1)},...,v_{\sigma(k)}\eta(v_{\sigma(k+1)},...,v_{\sigma(k+l)}) $

and \begin{equation} (\omega\wedge\eta):=\sum_{i_1<...

So how can i find the relation between these two defininitions? Any hint or help is appreciated.

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    Your first formula is false: $\omega \wedge \eta = \frac{1}{k!l!}\text{Alt}(\omega \otimes \eta)$2017-02-01
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    You're right. Thanks2017-02-01

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