How can we solve the following indefinite integral? $$ \int(\sqrt{1-x^3}-\sqrt[3]{1-x^2})dx $$
What about $\int_0^1(\sqrt{1-x^3}-\sqrt[3]{1-x^2})dx$?
Some definite and indefinite integrals
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calculus
integration
definite-integrals
indefinite-integrals
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2$$y^2+x^3=1$$ and $$y^3+x^2=1$$ we need to find the area of the same curve – 2017-02-01
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1See here: http://www.wolframalpha.com/input/?i=integrate+(1-x%5E3)%5E(0.5)-(1-x%5E2)%5E(1%2F3) – 2017-02-01
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0@M.H.Hooshmand The limits of integration are $ x=0, x=1$ .Throughout this interval the $y=f(x)$ has real values.So you can find the areas under curve from their integrals and find out the difference..A part of the difference curve is above $x-$ axis and another part of the difference curve is below $x-$ axis. – 2018-05-15