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I have two sequences $$1,2,3,1,2,3,1,2,3,1,2,3,\cdots$$ and the second sequence is $(-1)^n$.

I am saying that both the sequence have no limit point but my friend is saying both the sequence have limit point

Which is correct, please help...

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    None has a limit. – 2017-02-01
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    Have a look at [this question](http://math.stackexchange.com/q/577198/75923) and the answer to it. There is an essential difference between [limit points of sets](https://en.wikipedia.org/wiki/Limit_point) and [limit points of sequences](http://planetmath.org/limitpointsofsequences). That might be the cause of confusion. – 2017-02-01

3 Answers 3

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Neither sequence has a limit because for both sequences, the claim

$$\exists L: \forall \epsilon > 0 \exists N\in\mathbb N\forall n\in\mathbb N: n>N\implies |L-a_n|<\epsilon$$

or, in writing:

There exists an $L$ such that, for all $\epsilon>0$, there exists some $N$ such that $|L-a_n|<\epsilon$ is true for all $n>N$

is false.

You can show the claim is false by showing that its negation,

$$\forall L\exists \epsilon > 0\forall N\in \mathbb N\exists n>N: |L-a_n|\geq\epsilon$$

is true.

An easier way to disprove the claim, of course, is to show that both sequence have two subsequences with different limits, and that is only possible if the sequence is not convergent.

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    @Arthur thanks. – 2017-02-01
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    Indeed no limits. But how about [limit points](http://planetmath.org/limitpointsofsequences) (of sequences, I mean)? – 2017-02-01
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The definition is: A point $l$ is said to be a limit point of a sequence $\{a_n\}$ if every neighborhood of $l$ contains infinite terms of the sequence. The limit points of first sequence are $1,2,3$ and for the 2nd sequence the limit points are $-1$ and $1$. As every neighborhood of $1$ contains infinite terms: namely $a_{3k+1},~ k=0,1,2...$ so $1$ is a limit point of the first sequence. Similarly you can do for other points

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    Really? Writing nbd because neighborhood is too much work? – 2017-02-01
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    @5xum Is the explanation wrong?? – 2017-02-01
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    Please elaborate..I think something is missing – 2017-02-01
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    @AbhishekChandra I think you have asked about limit points of the sequence and not limit of the sequence. Clearly these two sequences have no limits but aren't $1,2,3$ the limit points of the first sequence?? If not, then what is the definition of limit point of a sequence?? – 2017-02-01
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Terminology: "Limit" and "limit point" are different things. (The style in German would be to make "limitpoint" a new word, to distinguish it from "limit".)

A sequence $(a_n)_n$ converges to the limit $a$ iff for all $r>0$ the set $\{n:|a-a_n|\geq r\}$ is finite. Equivalently that for all $r>0$ the set $\{n: |a-a_n|

A value $b$ is a limit point of $(a_n)_n$ iff for all $r>0$ the set $\{n:|b-a_n|

A sequence may have many limit points, or none. A sequence $(a_n)_n$ has exactly one limit point $a$ iff $(a_n)_n$ converges to $a$