Show that:
|z|=1 if and only if 1/z=z bar (z bar is the complex conjugate)
I have:
|1/z|*|z|=|(1/z)*z|=|1|=1
Show that the absolute value of z = 1 iff...
0
$\begingroup$
complex-numbers
-
1Hint: $|z|^2=z \bar z\,$. – 2017-02-01
-
0thanks for the hint, I can give you credit if you write a response – 2017-02-01
-
0Thanks, but that was just a hint. Instead, I'd be happy to give *you* a +1 if you wrote a full answer (yes, it's perfectly acceptable around here to post an answer to one's own question). – 2017-02-01
-
1It was really easy after your hint and I'm so exhausted haha, thanks again. – 2017-02-01