For $n,m \in \mathbb{Q}$, is $n=m, n=-m$ an equivalence relation?
This problem seems trivial as it is clearly symmetric, transitive and reflexive. Am I missing something?
Equivalence Relations Help
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discrete-mathematics
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1If the coma in $n=m,n=-m$ means *or*, then you are not missing anything. – 2017-01-31
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1No, you are right, it is an equivalence relation, where each rational is related only to it's additive inverse, and itself. – 2017-01-31