I tried using $[x][y]=[xy]$ but clearly, that is wrong
I know that $\lim_{x→0}[\sin(x)x]=0,\lim_{x→0}[\sin(x)x]=0$ and $\lim_{x→0}[\tan(x)x]=1$.
I tried using $[x][y]=[xy]$ but clearly, that is wrong
I know that $\lim_{x→0}[\sin(x)x]=0,\lim_{x→0}[\sin(x)x]=0$ and $\lim_{x→0}[\tan(x)x]=1$.
One can see that
$$\frac{x^2}{\tan(x)\sin(x)}=\frac{\cos(x)}{\left(\frac{\sin(x)}x\right)^2}$$
thus, the limit is $1$ without the floor function $[\cdot]$. With the floor function, we can deduce the limit will be $1$ or $0$, depending on which side $\frac{x^2}{\tan(x)\sin(x)}$ approaches $1$. We can deduce which side the limit falls on by observing the following:
$$\tan(x)\sin(x)-x^2>0\text{ for }|x|
which follows from taking the Maclaurin series expansion.
Thus, the limit is $0$.