How can I get CDF from this PDF:
Mine solution is: 
, but I'm not sure if that's correct.
How to get CDF from PDF
0
$\begingroup$
probability
functions
1 Answers
1
Yes, indeed: $$\int_{x_m}^x \alpha x_m^\alpha s^{-1-\alpha}\mathbf 1_{s>x_m}\operatorname d s = (1- x_m^\alpha x^{-\alpha})\mathbf 1_{x>x_m}$$
Your answer was mostly okay, but missed noting the support for the random variable.