I had the differential equation $$(x^{y+1}x\ln x - x^2 y^x)y' = y^{x+2}\ln y - x^y y^2$$ and simplified it to
$$x(xx^y(y'\ln x)+yx^y (yx^{-1})))+y(yy^x(\ln y)+xy^x(xy^{-1}y'))=0$$
But what to do next ? Any hints?
Solving $(x^{y+1}x\ln x - x^2 y^x)y' = y^{x+2}\ln y - x^y y^2$
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ordinary-differential-equations
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0i think a numerical way is the best idea – 2017-01-30
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0Is this an exercise or an actual problem you are trying to solve? – 2017-01-30
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0@MrYouMath A friend gave it to me. I'm not sure from where he got it from. – 2017-01-30