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$f:R→R$ is twice differentiable. $f$ and $f''$ are bounded. How to prove with Taylor-theorem that $f'$ is bounded as well?

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    What's restricted?2017-01-28
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    What does "resctricted function" mean here?2017-01-28
  • 0
    Do you mean "bounded"?2017-01-28
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    yeah, sorry, I mean bounded.2017-01-28

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For any $x$, by Taylors theorem, $$f(x+1) = f(x) + f^\prime (x) + \frac{1}{2}f^{\prime\prime}(\xi)$$

for some $\xi\in (x, x+1)$. Now solve for $f^\prime(x)$.

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    smart solution! :)2017-01-28