Suppose a runner runs $400$ meters and this is the function at which he runs at $m(t) =0.1t^2+3t$ I know $t=50$ when it's $400 \text{ m}$ what I want know is how can I know the speed at which he was going at at the very last moment. I've tried looking for the answer but I can't find anything. Please help.
What is the speed of this function $m(t) =0.1t^2+3t$ at the very last moment
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calculus
1 Answers
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Take the derivative of m(t). If m(t) represents position, m'(t) represents velocity!
$m'(t) = 0.2t + 3$.
$m'(50) = 0.2(50)+3 = 13$ meters/sec.