In this example(Calculus Made Easy pg 126): $\frac{4R^2-2x^2}{\sqrt{4R^2-x^2}}=0$ simplifies to $4R^2-2x^2=0$ and therefore $x=R\sqrt{2}$ Why does the denominator not come into play when we equate to zero?
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1It does come into play. Multiply both sides by the denominator, what do you get? – 2017-01-28
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0zero divided by any real number equals zero - provided $x>2R$ you won't have an issue. – 2017-01-28
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0Ahh, I see now. Thanks I feel like I should have seen that before I asked. – 2017-01-28