without using actual division method, find the quotient and remainder when $x^6-2x^4+x^2+5$ is divided by $x^2-2$.
Using Remainder Theorem I got the remainder as $7$ but how do I get the quotient..
without using actual division method, find the quotient and remainder when $x^6-2x^4+x^2+5$ is divided by $x^2-2$.
Using Remainder Theorem I got the remainder as $7$ but how do I get the quotient..
Let $\,X = x^2$ then $\,f-7 = X^3-2X^2+X-2 = (\color{#c00}{X-2})X^2 + \color{#c00}{X-2}$ is easy to divide by $\,\color{#c00}{X-2}$
$x^6-2x^4+x^2+5=x^4(x^2-2)+x^2-2+7=(x^4+1)(x^2-2)+7$
so quotient is $x^4+1$