2
$\begingroup$

I was going through Neukirch's algebraic number theory again (after years of not studying number theory), and found out that I marked a star on exercise 1.8.2. I tried to solve it again, but I had no idea where to start. The question is as follows:

For every integral ideal $\mathfrak{A}$ of $\mathcal{O}$, there exists a $\theta \in \mathcal O$ such that the conductor $\mathfrak F = \{ \alpha \in \mathcal O : \alpha \mathcal O \subseteq \mathcal o [\theta] \}$ is prime to $\mathfrak A$ and such that $L=K(\theta)$.

Notations : $\mathcal o$ is a Dedekind domain with field of fractions $K$, and $\mathcal O$ is the integral closure of $\mathcal o$ in a finite field extension $L$ of $K$.

It seems quite clear that this exercise is missing the assumption that the field extension $L/K$ is separable, so I will assume that.

I have no idea where to start -- I believe that the biggest problem is that I have absolutely no intuition about what a conductor is. The book gives few theorems about it, but I do not see what it actually is about.

Can someone please explain about this concept, or give some hints on this question? Thank you.

Edit : it seems that the exercise is wrong, but I still seek to understand what conductors are all about.

  • 0
    Wow! searched on mathSE because of my friend's kind advice, and found out that this question is indeed absolutely false. Poor me...2017-01-27
  • 0
    Reference : http://math.stackexchange.com/questions/47997/find-primitive-element-such-that-conductor-is-relatively-prime-to-an-ideal-exer2017-01-27

0 Answers 0