The type of graph that arises when drawing Pascal's triangle, see the link here. Only depends on one integer (the depth) and it is sort of like a binary tree after identifying certain vertices (of course it is no longer a tree then). I think they must have a name somewhere since they are fairly natural things to consider... but I can't find a name anywhere using Google.
Does this type of graph have a name?
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0That's just some lattice graph, isn't it? – 2017-01-26
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0In the example you linked, all paths end at the same node, not just at the same depth. – 2017-01-26
1 Answers
It's a triangular grid graph, which is a special case of a lattice graph.
Technically it also contains the horizontal connections, which are not part of your example, but they could as well be included.
EDIT: Without them it is actually just a square lattice grid as pointed out by @Joffan.
Citing Weisstein, Eric W. "Triangular Grid Graph." From MathWorld--A Wolfram Web Resource:
The triangular grid graph $T_n$ is the lattice graph obtained by interpreting the order-$(n+1)$ triangular grid as a graph, with the intersection of grid lines being the vertices and the line segments between vertices being the edges. Equivalently, it is the graph on vertices $(i,j,k)$ with $i,j,k$ being nonnegative integers summing to $n$ such that vertices are adjacent if the sum of absolute differences of the coordinates of two vertices is $2$ (West 2000, p. 391).
The graph bandwidth of $T_n$ is $n+1$ (West 2000, p. 392).
$T_n$ is also the hexagonal king graph of order $n$, i.e., the connectivity graph of possible moves of a king chess piece on a hexagonal chessboard.
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1Please put linked info into the actual answer. – 2017-01-26
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1If you don't have the horizontal connections, it's just a square lattice (although with a diagonal limit to it) – 2017-01-26
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0@Joffan Yes, good point. – 2017-01-26
