Am I suppose to plug in the fraction for cos into the equation above and find the other fraction to make it equal to 1 or is there more to this problem? Can someone please explain (
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Pythagorean Identity
-2
$\begingroup$
algebra-precalculus
trigonometry
2 Answers
1
Hint - you can derive formulas.
Formula 1 -
$\sin^2 \theta = 1 - \cos^2\theta$
$\sin \theta = \sqrt{1 - \cos^2\theta}$
Formula 2 -
$\cos^2 \theta = 1 - \sin^2\theta$
$\cos\theta = \sqrt{1 - \sin^2\theta}$
In your question you need formula 1.
0
Directly from the equations you have $\sin\theta=\sqrt{(1-\cos^{2}\theta)}$. You can do the rest.