Vector y, vector x, plane P. I will write $proj_p(x)$ and just $proj x$
What is $-2y\cdot projx - 2y \cdot perp x$
So it is
$-2y(projx + perpx ) = -2y\cdot(x) = -2 (y \cdot x)$ ? Is this right?
projection and perpendicular dot product type
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linear-algebra
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0you should explain more what the question asks cause it is very confusing – 2017-01-26
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0If $projx+perpx=x$ then what you wrote seems correct. And according to a certain likely guess what $projx$ and $propx$ mean, the equation is true. But that's still just a guess unless you can define your symbols. (It's best to _edit_ the question in order to show definitions.) – 2017-01-26