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So I'm taking calculus 2, having never taken physics and I'm having some trouble understanding the problems we are at.

I'm trying use integrals to calculate the force required to pump a container of water.

So far my teacher states that given the density of water $\rho = 1000\ \mathrm{kg/m^3}$ and the gravitational acceleration of the earth $g = 0.8\ \mathrm{m/s^2}$ we can determine that $1\ \mathrm m^3$ weighs $1000\ \mathrm g$ which is around $9800\ \mathrm N$.

I can't seem to figure out how he got to $9800\ \mathrm N$.

I'm trying to play with the density of water and the gravitational acceleration to get to 9800, but my units don't seem to add up.

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Well the force of gravity is equal to $mg=\rho V g=(1000 kg/m^3)(1 m^3)(9.8kg *m/s^2)=9800N$.

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    The way I see the units add up is (Kg/m^3)(m/s^2) shouldn't that give (Kg) / (m^2 * s^2) I'm lost with how you multiply density and gravity and end up with Newtons that are (Kg)(m/s^2) – 2017-01-25
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    You forgot to multiply by the volume: the units would be (kg/m^3)(m^3)(m/s^2)=(kg m/s^2) for density * volume * acceleration = force. – 2017-01-25