I have to find x in this equation. This is my first time encountering an expression with two -logs so I don't know which one goes in the denominator. The expression is:
$$\log_7(x+6) - \log_7(x-9) - \log_7(4) = 0$$
How do I simplify this expression to a single logarithm involving two -log?
0
$\begingroup$
algebra-precalculus
trigonometry
logarithms
1 Answers
2
Hint:
$\log_7(a) - \log_7(b)=\log_7\left(\frac ab\right)$
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0will this result to a complex fraction since there are two -log? – 2017-01-24
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0@Yeol $\log(a/b) - \log(c)$ can be simplified using the same rule. – 2017-01-24
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0will it be log((a/b)/c)? – 2017-01-25
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0@Yeol Yes. Now simplify the expression and you are done. – 2017-01-25