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If $u\gg0$ what is a good upper bound for $\sum_{i=1}^{u-1}\frac1{i(u-i)}$?

Is it $O(u^{-1})$? I am looking for precise scaling.

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    The sum isn't defined because of the last term.2017-01-24
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    @YvesDaoust corrected.2017-01-24

1 Answers 1

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$$\sum_{i=1}^{u-1}\frac1{i(u-i)}=\frac1u\sum_{i=1}^{u-1}\left(\frac1{u-i}+\frac1{i}\right)=\frac{2H_u}u,$$

which is asymptotic to $$2\frac{\ln(u)+\gamma}u.$$

For an upper bound, read "the Best Lower and Upper Bounds of Harmonic Sequence, Chao-Ping Chen and Feng Qi".

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    Yepp $\,(+1)\,$2017-01-24