We all know that the solution to the isoperimetric problem in the Euclidean plane is the circle. Unfortunately, the circle does not tile the plane without adding at least 2 bowed in triangles. Because of the shape formed by adding the triangles I looked at prototiles formed by the function: $f(j):=\begin{cases} Sin[x-\frac{1}{4}(3+(-1)^{1+j})\pi]^j+\frac{1}{2}(3+(-1)^{1+j}) & \\ Sin^j[x] \end{cases},\frac{\pi}{2}\leq \theta\leq \frac{(4+(-1)^{1+j})\pi}{2}, j \in \mathbb{N}$
I would show the first 12 examples but can't embed pictures yet.
I wrote an essay for fun on why they are nice and have a small perimeter to area ratio for a given string of fixed length and indicated that the best answer was likely for j=1,2 without proof. But they are not smooth all the way around since they have two cusp points on the left and right ends. I was wondering if there is any previous research generalizing the isoperimetric theorem to tilings. Is my function for j=1,2 the best? Does a tiling that is smooth all the way around the centroid exist?