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A dice is thrown until number $6$ appeared. What is the probability that at least three throws were necessary, if $6$ didn't appeared in the first throw.

  • 1
    To say that it took at least three throws to get the first 6 is the same as to say that 6 didn't appear in the first two throws.2017-01-22
  • 0
    Quibble: 'mouse/mice' ... 'die/dice'.2017-01-23

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The probability of a 6 appearing on the second throw is 1/6 since there was no 6 on throw #1. So the probability is just 1-1/6=5/6.