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I'm trying to plot this function: $\sqrt[3]{3-x}$ in Mathematica. I have tried various numbers in Y range and X range, but wolfram only shows half of the graph. Google or desmos.com plot the correct function.

http://i.imgur.com/XyMi0ND.png

Any help is appreciated.

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    Saying that a graph is "wrong" is ... wrong. It is a different interpretation. – 2017-01-22

2 Answers 2

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Plot[Sign[#]Abs[#]^(1/3)&[3-x], {x,-1,7}]
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    Funny, this works but the command the OP used doesn't work. Why is it? – 2017-01-22
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    @RSerrao Because Wolfram gives a nonreal result for $\sqrt[3]{y}$ when $y < 0$, and representing $e^{\pi i/3}\sqrt[3]{\lvert 3-x\rvert}$ for $x > 3$ in a two-dimensional plot isn't so easy, I think. – 2017-01-22
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For me Plot[CubeRoot[3 - x], {x, -12, 12}] is working.

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    Funny, this works but the command the OP used doesn't work. Why is it? – 2017-01-22
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    I think that Mathematica considers the expressions of the form $(x)^{1/n}$ only for $x \geq 0$. Otherwise you have to specify $Sqrt$ or $CubeRoot$. – 2017-01-22