The question title says it all.
Book I, Proposition 24 states
If two triangles have two sides equal to two sides respectively, but have one of the angles contained by the equal straight lines greater than the other, then they also have the base greater than the base.
Book I, Proposition 18 states
In any triangle, the angle opposite the greater side is greater.
It seems that Proposition 24 proves exactly the same thing that is proved in Proposition 18.
Does Proposition 24 prove something that Proposition 18 (and possibly Proposition 19) does not ?
It seems that Proposition 24 could be proved in a single step by invoking Proposition 18. What is the reason it could not be done that way ?... an example of why not, would be great.