I'm stuck at this problem and the solution doesn't make sense to me, I would like to understand what's wrong with my reasoning.
There is a cylindrical tank with height 15m and radius 10m, fluid is being pumped into a biddon, which is composed of a rectangle and a prism (see picture).
We know that the liquid level is decreasing with 2cm/sec in te cylindrical tank, and want the rate the level increases in the biddon at a level of 6m
My way of solving is first calculate $V^\prime$.
$V=hr^2\pi$ so $V^\prime=\pi r^2h^\prime\, \to\, V^\prime=10000(2\pi)=20000\pi$
Then for the body I split up in two parts, First $V=1000(1500h)$
Second $V=(800\cdot1500h)/2$
(I did $\frac{30}{10}=\frac{x}{6}\,\to\,x=18$ and $b=18-10$)
Added them together $V=15\cdot10^5h+6\cdot10^5h \,\to\, 21\cdot10^5h$
Then $\frac{V^\prime}{21\cdot10^5}=h^\prime$ so $h^\prime=0.01496\,$cm/sec
However the result should be 0.019 cm/s, and it involves the height of the cylinder, but I don't see how that matters, or why my way is wrong.
I would really appreciate your help :)
