$$f(x)=(1/2)e^{-|x|}$$ How should I go about solving this problem? I need to find the CDF of the given PDF. The absolute value is throwing me for a loop.
Finding the CDF of a given PDF
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$\begingroup$
probability
probability-distributions
1 Answers
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$F(x) = \begin{cases} \int_{-\infty}^x \frac 12 e^x dx &x\le0\\ \int_{-\infty}^0 \frac 12 e^x dx+ \int_{0}^x \frac 12 e^{-x} dx &x>0 \end{cases}$