Here :
I asked for an irrational number with digits $0$ and $1$, such that the continued fraction has no entry larger than $9$
The number
$$0.1011100100100000000000100000\cdots$$
with ones at the positions
1 3 4 5 8 11 23 38 77 155 311 623 1247 2495 ...
seems to satisfy the condition. From $38$ on, the next position is at $2p+1$, if the previous position is at $p$
The finite decimal expansion (truncation at the $1$ in position $2495$) has the property that no entry of the continued fraction is larger than $9$, but what about the irrational number formed this way ? Can we prove that it has the property as well ?