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enter image description here For a skew symmetric matrix of higher order . how do we find the determinant in short cut

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    In general, you do not. However, in this case your luck is having a skew-symmetric matrix of odd order: what's $\det(-A)$ ? – 2017-01-20
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    Hint: $A = -A^t$, then $\det (-A) = (-1)^n \det A$. – 2017-01-20

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$$Det(A)=Det({A^T})=Det(-A)= Det(-I\cdot A) = Det(-I)\cdot Det(A)=(-1)^5Det(A).$$

We deduce $$Det(A)=0. $$

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    Smart work . and I was labouring out. :-) – 2017-01-20
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    ...from this we see that for all **odd** $n$ det. of sk.-sym. m. is equal $0$. – 2017-01-20