One has to show that
$$||z| - |w|| \leq |z + w|; z,w \in \Bbb{C}$$
I proceeded as follows:
because of the symmetry on my next step, I can assume WLOG that $|z| \geq |w|$; Therefore $||z| - |w|| = |z| - |w|$:
$$|z| - |w|\leq |z + w| \iff\\ (|z| - |w|)^2 \leq |z+w|^2\iff \\ |z|^2 - 2|zw| + |w|^2 \leq (z+w)(\bar{z}+\bar{w})\iff\\ z\bar{z} + w\bar{w} - 2|zw| \leq z\bar{z} + w\bar{w} + z\bar{w} + \bar{z}w\iff \\ -2|zw| \leq 2Re(z\bar{w})$$
which is obviously true given that the LHS is $\leq 0$ and the RHS is $\geq 0$. I was wondering, however, if one could tackle this problem in a different way, making use of elementary tools only, to prove that inequality. I am particularly interested in knowing if there is any "obvious" way of applying the triangle inequality here.