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$$A=\cfrac 6 {\cfrac 6 {\cfrac 6 {6-\cdots}-5}-5}-5 :A=\text{?}$$ my try :

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But I want to recurrence Sequence method!!

$$a_{n+1}=\frac{6}{a_n}-5: a_1=\text{?}$$

$$a_2=\frac 6 {a_1}-5,$$

$$a_3=\frac{6}{a_2}-5$$

???

thank you very much !

  • 3
    Try the recursion $a_{n+1} = \frac{6}{a_n} - 5$2017-01-18
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    @Winther. Continuation?!!2017-01-18
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    You could try to show that it converges for some suitable initial value(s) $a_0$?2017-01-18
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    @Winther. a_1 = ?2017-01-18

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$A=\dfrac{6}{A}-5\\A^2=6-5A\\A^2+5A-6=0\\(A-1)(A+6)=0\\A=1\text{ or }-6$