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I just wish to confirm if my understanding is correct for the following problem: if there are 5 women and 5 men, how many possibilities exist to form a committee of 3 women and 2 men. so i have computed this problem as below

5C3 x 5C2 = 100 possibilities.

is this correct?

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    Yes, that looks good. Note that you have enough privilege to use [the chatroom](http://chat.stackexchange.com/rooms/36/mathematics) – 2017-01-18

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Yes. $\binom{5}{3} \times \binom{5}{2} = 100$ is correct.