Sometimes you need to add some lines to the diagram.
Since you're looking for horizontal and vertical forces,
draw vertical and horizontal lines in both directions from
the point where all the force arrows start.
It looks like two of the vectors were meant to be vertical
or horizontal already. So when you draw the vertical and horizontal lines,
they will be collinear with the arrows depicting those two vectors.
A vector perfectly aligned with a horizontal line
is its own horizontal component (its vertical component is zero).
Likewise a vertical vector is easily split into components
(one of which is just zero).
You have one vector where you need trigonometry.
It has a $125$-degree angle measured from the vertical line,
but you can use that fact to figure out its angle from the
horizontal line.
That gives you an angle less than $90$ degrees and it's
easy to draw a right triangle using that angle.
Alternatively, knowing you have a $125$-degree angle with the vertical line
above the vector, and knowing that two angles making a straight line
must sum to $180$ degrees, you can figure out the angle the vector
makes with the lower part of the vertical line
and use that angle to draw a right triangle.
As noted in one of the comments, an important thing to notice is that
there really are three vectors in the figure. Two of them happen to be
already aligned with the axes, which makes it very easy to identify their
components, but that does not make those two vectors somehow be components
of the third vector.
When you get more comfortable with components and computing them using
the sine and cosine functions (so that you don't need to actually
identify triangles to find the components each time), it will be useful to
learn how to use the sine and cosine functions to
deal directly with angles greater than $90$ degrees.
For example, for angles in degrees, $\cos(180 - x) = -\cos(x)$.
But that might be a slightly more advanced topic for a later time.
