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A ship is travelling at night in perfectly calm seas at a speed (relative to the surrounding sea) of 40 km h−1 with a bearing of 120◦ . It is on course to enter harbour in the morning assuming no change in the sea conditions. Unfortunately, during the night, unknown to the crew, a strong current arises, of 10 km h−1 in the direction from south-west to north-east

If the ship was 300 km from the harbour when the current arose and heading at right angles to a shore that is approximately a straight line, by how much will the ship miss the harbour because of the current? Give your answer to the nearest km

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    I calculated the magnitude of the ships velocity as 44 in a direction of 107 degrees but am having a brain fog and would be grateful for fresh pair of eyes. Dont know how im finding such a simple question so difficult – 2017-01-17
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    What is the ship’s real velocity vector if you add in the current? – 2017-01-17

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