I have the following question:
And i am asked to calculate the distance, d,.
However, i am unsure how to do this. I know that in order for the see-saw to be in equilibrium then both sides should have equal weights.
calculate distance from centre
-1
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classical-mechanics
2 Answers
2
HINT:
You have to balance out the turning force on both sides.
$1 \times 400 = 0.5 \times 200 + d \times 250.$
Solve for $d$.
1
Since the see saw is in rotational equilibrium, net torque acting on system is zero. Hence, we have: $$(400*1.0) - (200*0.5) - (250*d) = 0$$