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Logarithm-question:

Using $\log_{24}(12)$, find $\log_{24}(6)$

Thanks.

  • 0
    You have few minutes earlier ask same type of question. It means you are not getting basics behind that. – 2017-01-16
  • 0
    http://math.stackexchange.com/questions/2100388/quick-logs-question-use-log-24-12-to-find-log-24-2 – 2017-01-16

1 Answers 1

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Let $\log_{24}12=x.$

Then $\log_{24}2=\log_{24}24-\log_{24}12=1-x.$

So $\log_{24}6=\log_{24}12-\log_{24}2=2x-1.$

Here's verification:

$(\log_{24}12)\cdot 2-1=\log_{24}12+\log_{24}12-\log_{24}24=\log_{24}(\frac{12\cdot 12}{24})=\log_{24}6.$

  • 0
    A numerical Value is needed. – 2017-01-16
  • 2
    Well, take whatever you had for $\log_{24}12$ and use y=2x-1 to get your answer. – 2017-01-16