Suppose, a function $T(N)$ is defined as follows :
$T(N)=\begin{cases} & \text{ $0$ }\ ; N< 1 \\ & \text{ $1$ }\ ; N= 1 \\ & \text{ $T(N-2) + T(N-3)$ }\ ; N> 1 \end{cases}$
Then, $T(N)$ = ?
Suppose, a function $T(N)$ is defined as follows :
$T(N)=\begin{cases} & \text{ $0$ }\ ; N< 1 \\ & \text{ $1$ }\ ; N= 1 \\ & \text{ $T(N-2) + T(N-3)$ }\ ; N> 1 \end{cases}$
Then, $T(N)$ = ?
To compute $T(12)$, the values of $T(10),T(9),\ldots,T(1),T(0),T(-1)$ will need to be computed, and no others.