How many ways are there to distribute $100$ different balls into $5$ different boxes so the last $2$ boxes contains even number of balls and first $3$ boxes contains balls more than $5$ and less than $20$ ?
For last $2$ boxes, I can apply the series $\left(1+\frac{x^2}{2!}+\frac{x^4}{4!}+\cdots\right)^2$
For the first three boxes, I am using the series as $\left(\frac{x^6}{6!}+\frac{x^7}{7!}+...... +\frac{x^{19}}{19!}\right)^3$
Am I right here or missing anything ?