I wouldn't expect that to yield anything useful.
Löb's theorem is fundamentally a negative result. What it does is to pull the rug under this otherwise intriguing proof strategy:
I want to prove $\psi$ (within $T$), but that seems to be hard. Instead I will use some kind of non-constructive meta-reasoning (that is formalizable in $T$) to show that a proof of $\psi$ must exist (even though I may not learn how that proof works), and then also prove $\operatorname{Prov}_T(\varphi)\to \varphi$ for a class of statements that includes my $\psi$. Then, combining those two parts, I will have proved $\psi$.
Löb's theorem tells us that this strategy is fundamentally flawed, because if you manage to complete the "easy" part $\operatorname{Prov}_T(\varphi)\to \varphi$, then you actually don't even need the non-constructive meta-reasoning that looked like the clever shortcut at first.
The lesson we learn is that proving $\operatorname{Prov}_T(\varphi)\to\varphi$ is harder than it looks -- you can't prove this for some nice general syntactically recognizable class of $\varphi$s unless it's because every $\varphi$ in that class is true (in which case having a particular proof in your hands is not very exciting).
In other words, proving $\operatorname{Prov}_T(\varphi)\to\varphi$ inescapably needs to involve reasoning about the particular thing that makes $\varphi$ true, rather than just things that would make us trust a separately given proof of $\varphi$. And if you're doing that kind of reasoning anyway, the argument goes, you might as well be proving $\varphi$ directly. That doesn't look like the makings of a shortcut.
(There are some "unnatural" exceptions to this where $\varphi$ is something you construct using the fixpoint theorem with the express goal of making $\operatorname{Prov}_T(\varphi)\to\varphi$ necessarily true. But that's explicitly not what you're asking).