Problem:
Prove that if $n < m$ with $n,m \in \mathbf{Z}$ and $x>1$, then $x^n < x^m$.
Proof:
Since $ x > 0$, we know $x^n > 0$.
Also, since $m > n$, it follows that $m - n \geq 1$. Thus $x^{m-n} > 1$.
Finally, $x^n(x^{m-n} -1) > 0$. Rearranging yields the desired result: $x^n < x^m$.
Question: I hope my proof is correct. I am actually curious whether it is possible to prove this result using induction? Could you somehow map $n,m$ from $\mathbf{Z}$ to the positive integers?