-3
$\begingroup$

I have this question

$g(x) = x^{2x+1}$

$h(x) = \frac{16-x^2}{x-9}$

$k(x) = \{(0,1), (1, 6), (2,6),(3,4),(4,6)\}$

and

$f(x) = g(h(k(x)))$

How do you find $f(4)$?

(I have no idea how to do this)

Thanks!

  • 3
    What do you mean by $k (x)=$a set of points? – 2017-01-13
  • 0
    @MichaelMcGovern, recalling my 9th grade math book, I'm pretty sure that means that $k(x)$ is the arbitrarily defined function (not a mathematical function) with a range of ${0,1,2,3,4}$ and a domain of ${1,4,6}$ with mappings as shown. – 2017-01-14
  • 0
    The question was updated to make it more specific. – 2017-01-14
  • 0
    Here $f(4) = g(h(k(4)))$. You evaluate the composition as one does with parentheses generally, by starting with the innermost expression, and working outward as each function is evaluated. – 2017-01-14

1 Answers 1

1

Compute $k(4)$.

Take the answer and use it as input for the function $h$ (in other words, compute $h(k(4))$).

Take the answer and use it as input for the function $g$.

The answer will be $g(h(k(4)))$, which is another way of saying $f(4)$.