I tried to look up the inverse of the function in the picture, but I don't understand what wolfram alpha gives me as an answer, can someone help me?
Inverse of a function in wolfram alpha
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$\begingroup$
roots
inverse
wolfram-alpha
inverse-function
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0Mathematica can't solve the equation $$y=\frac{4x^5}{1+x^2}$$ in explicit form – 2017-01-13
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0Alright thanks, are there any methods to find the inverse of such a complex function? – 2017-01-13
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0It's also possible to obtain the power series for the inverse (near a given point), or to obtain approximations for the inverse as $y \to \pm \infty$. – 2017-01-13