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Use matrix methods to find the general solution of the equations $$\dot x=3x+2y,\space \dot y=-5x-3y$$ Sketch the phase-plane trajectories in the vicinity of the origin.

I wrote the equations as $\mathbf {\dot X}=\begin{pmatrix}3 & 2\\-5 &-3\end{pmatrix}\mathbf X$ where $\mathbf X=\begin{pmatrix} x\\y \end{pmatrix}$. I eventually get $$\mathbf X= A\begin{pmatrix} -2\\3+i \end{pmatrix}e^{-it}+B\begin{pmatrix} -2\\3-i \end{pmatrix}e^{it}$$ As the eigenvalues here ($i, -i$) are purely imaginary with have ellipses centred at $(0,0)$. My question is:

How do we determine the handedness of the ellipses (and also if possible details of them such as major/minor axis, but I'm not sure this is needed)?

Thank you

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The unit tangent vector of the trajetory:

$$\mathbf{T}(x,y)=\frac{(3x+2y,-5x-3y)}{\sqrt{34x^2+42xy+13y^2}}$$

Refering to the sketch of the vector field $\mathbf{T}(x,y)$ below, it's clockwise.

enter image description here