Can anyone show how to simplify $$\frac{\sum_{n=1}^\infty n\frac{n^{n-1}}{n!}x^{n-1}}{(-1+\sum_{n=1}^\infty \frac{n^{n-1}}{n!}x^n)^2}$$
solving power series expression?
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$\begingroup$
combinatorics
power-series
2 Answers
5
small hint
the derivative of $$\frac{1}{1-f}$$ is
$$\frac{f'}{(-1+f)^2}.$$
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0And starting from this (not so small) hint, a beautiful function appears. $+1$ – 2017-01-12
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0whats the function – 2017-01-12
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Hint: The Lambert W function admits the expansion \begin{align*} \sum_{n=1}^\infty n^{n-1}\frac{x^n}{n!}=-W(-x)\qquad\qquad |x|<\frac{1}{e} \end{align*}