Solve $2\cos (2\theta) = 4\sin\theta$ for all values of $\theta$ between $0^{\circ}$ and $360^{\circ}$

Question

Solve $2\cos (2\theta) = 4\sin\theta$ for all values of $\theta$ between $0^{\circ}$ and $360^{\circ}$.

I have already tried to solve this but I am unsure as to finding out this particular one.

Answer 1

$$4\sin\theta=2\cos2\theta=2(1-2\sin^2\theta)$$

$$\iff2\sin^2\theta+2\sin\theta-1=0$$ which is a Quadratic Equation in $\sin\theta$

Remember for real $\theta,-1\le\sin\theta\le1$