How do you simplify $$e^{{147i}\left(\frac{1-\left(\frac{1}{e^{8i}}\right)^{10}}{1-\frac{1}{e^{8i}}}\right)}$$ in terms of cis?
I was trying to solve a question that was a geometric series and am now stuck on how to simplify this. Any help?
How do you simplify $e^{{147i}\left(\frac{1-\left(\frac{1}{e^{8i}}\right)^{10}}{1-\frac{1}{e^{8i}}}\right)}$ in terms of cis?
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algebra-precalculus
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0What is "cis" ? – 2017-01-11
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0$\cos\theta+i*\sin\theta$ – 2017-01-11
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0Pretty sure $\cos(n)+i\sin(n)=e^n$, so I'm basically asking for what the exponent of $e$ is. But I'm not sure what form the answer is. – 2017-01-11
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0Not quite. Given $n\in\mathbb{R}$, then $\cos(n)+i\sin(n)=e^{i\cdot n}\neq e^{n}$. If you can simplify the exponent, using cis is easy if you want it in that form – 2017-01-11
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0oops srry that's what I meant – 2017-01-12