How do i solve this one using exponential function? should i bring up x^2? $$\int\frac{2^{\frac{1}{x}}}{x^2}dx$$
Integral of exponential function?
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$\begingroup$
integration
exponential-function
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0U-subsitution is a nice way to proceed, do you see anything in the integrand that would be useful to set equal to u? – 2017-01-11
1 Answers
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$$t=(1/x)$$,$$-dt=\frac{dx}{x^2}$$$$\int2^tdt=\frac{2^t}{\ln2} +C$$
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0why the derivative of t become negative? and became x^2? – 2017-01-11
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0$t=x^{-1}$ now differentiate it $dt=-x^{-2}dx$ – 2017-01-11