Using yaw angle $\theta$ and velocity $v$, the curvature $c$ can be calculated according to:
$$ c = \frac{\dot{\theta}}{v} $$
Given are discrete values for the yaw angle $\theta_t$, velocity $v_t$ and their corresponding standard deviations $\sigma_{\theta_t}$ and $\sigma_{v_t}$.
Can you explain me how to calculate the standard deviation of the curvature $\sigma_{c_t}$ using the given terms?
I though of using the ratio of the standard deviations for the yaw angle and the velocity but this seems to be wrong because there is no closed formula for the variance of a ratio. I cannot use a Taylor approximation since I don't have an analytical formula, only a few discrete values (approx. 800).
Note that the yaw angle and the velocity are uncorrelated.
To compute the angle derivative I use
$$ \dot{\theta} = \frac{\theta_{t+1} + \theta_{t}}{\Delta t} $$
With this in mind, the variance should be:
$$ var(\dot{\theta}) = var(\frac{\theta_{t+1} - \theta_{t}}{\Delta t}) = \frac{1}{\Delta t ^2} (var(\theta_{t+1}) + var(\theta_{t})) $$