How do you get the roots of the equation in algebraic form? I have no idea after changing to a trigonometric form. The angle was not simple.
$z^4- \sqrt3 i+1=0$
Roots of a equation on a complex plane
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$\begingroup$
complex-numbers
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0But the angle _is_ simple. Look again. – 2017-01-10
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1$z^4=2(\ldots)$ – 2017-01-10
1 Answers
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Hint: We have $$z^4 =\sqrt {3}i-1 =2 (\frac {\sqrt {3}}{2}i-\frac {1}{2}) =2 (\cos 120^\circ +i \sin 120^\circ) $$
Can you take it from here?
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0Yes, I got the answer. thanks. – 2017-01-10