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Given an angle ∠ABC and an arbitrary point D somewhere within the angle, how would you (using only a compass and straight edge) draw a line segment where one end lies on AB and the other on BC, with D being the midpoint of the segment?

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  1. Let $B'$ be the symmetric of $B$ with respect to $D$;
  2. Let $A'\in BC$ be such that $B'A'\parallel BA$;
  3. Let $C'\in BA$ be such that $B'C'\parallel BC$;
  4. $BC'B'A'$ is a parallelogram, hence $D$ is the midpoint of $A'C'$. enter image description here