The actual textbook question:
An integer valued random variable $X$ has p.m.f. $f$ satisfying $$f(x)=\frac{\alpha+\beta x}{x}f(x-1)\quad...(*),\quad\beta \ne1\quad\text{and}\quad x=1,2,...$$Find $\mu,\mathrm{Var}(X)$ and $\mathrm{MD}_{\mu}$ where $\mu=\mathrm{E}(X)$.
While this problem was solvable by cross-multiplying the recursive equation of $f$ and summing up both sides for all possible $x$ to find the required moments, I wasn't able to find out the exact closed-form expression for $f$. I realise that we don't need the exact expression to find the required quantities, but is it possible to solve for $f$ from the given relation? The source adds that the binomial and Poisson random variables are of this type.
Putting the values of $x$ in $(*)$ for a finite number of times from $x=1$ to $x=n$ and multiplying the $n$ equations I get, $$f(n)=\frac{f(0)}{n!}(\alpha+\beta)(a+2\beta)...(a+n\beta)$$
Then I could perhaps write $\displaystyle f(x)=\lim_{n\to\infty}f(n)=\frac{f(0)}{n!}\lim_{n\to\infty}p_n$, (say).
Applying the AM-GM inequality on $p_n$, I could again possibly say that $$\lim_{n\to\infty}p_n=\lim_{n\to\infty}\left[\alpha+\frac{\beta (n+1)}{2}\right]^n,\quad\text{which diverges}.$$
I don't think using $\sum_{x=1}^{\infty}f(x)=1$ helps me out here.