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I really need help with this problem, I don't seem to understand it all... I've drawn out the diagram but I don't know where to begin. I would like a hint, to help me understand how to solve this problem or where to begin.

Let $ABCD$ be a square of side length $1234$. $E$ is a point on $CD$ such that $CEFG$ is a square of side length $567$ with $F$ and $G$ outside $ABCD$. The circumcircle of triangle $ACF$ meets $BC$ again at $H$. Find $CH$.

After this diagram is drawn and all the points are labeled,I need to find the length of $CH$. But for me it is unclear where to begin with this problem, such that using the information given, I can find out the length of CH.

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    Hint: $AC\perp CF$. – 2017-01-08
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    $AF$ is a diameter, so the midpoint of that line is a horizontal axis of symmetry for the circle. Thus $|BH|=567$... – 2017-01-09

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